Here's one for your astro boffins. I want to know how far the earth tilts in miles between the summer and winter equinoxes at Wellington New Zealand from these co-ordinates 41°17'11.9"S, 174°46'32.05"E.
Given the the earth "wobbles' about its axis as it orbits the sun. This gives the seasonal variations. Summer is when the earth tilts closer to sun and visa versa. How does one calculate the distance at that point?
Hi Wayne....The angle of tilt doesn't change from summer to winter. It's stay's at the same 23.5% degrees. The sun's just on the far side of the axis. I think you want to know the difference in the sun's seasonal zenith at those co-ordinates....I'm working on it.
Edited by - nakigreengrass on 05/19/2020 22:51:06
That seasonal difference is really obvious when you live in a mountain valley.
The zig-zag mountain ranges east and west of my house raise hell with the numbers for a flat horizon.
Some times, the sun is rising in a gap between peaks, sometimes hidden behind a peak.
Hard to really call it a sunset at the winter solstice at my house.
The sun goes behind a peak at 1:52 PM.
I'm at nearly 53 degrees north. Paul, you can skip the % notation = it isn't useful.
Degrees, minutes and seconds of arc have always intrigued me.
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